SOLUTION: Can you please help me solve this? I'm supposed to factor using the formula {{{(a+b)(a^2-ab+b^2)}}} or {{{(a-b)(a^2-ab+b^2)}}} but I'm not exactly sure which one, and how to. {{{x
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Question 189583: Can you please help me solve this? I'm supposed to factor using the formula or but I'm not exactly sure which one, and how to.
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
Looking at we can see that the first term is and the last term is where the coefficients are 1 and -8 respectively.
Now multiply the first coefficient 1 and the last coefficient -8 to get -8. Now what two numbers multiply to -8 and add to the middle coefficient -7? Let's list all of the factors of -8:
Factors of -8:
1,2,4,8
-1,-2,-4,-8 ...List the negative factors as well. This will allow us to find all possible combinations
These factors pair up and multiply to -8
(1)*(-8)
(2)*(-4)
(-1)*(8)
(-2)*(4)
note: remember, the product of a negative and a positive number is a negative number
Now which of these pairs add to -7? Lets make a table of all of the pairs of factors we multiplied and see which two numbers add to -7
First Number | Second Number | Sum | 1 | -8 | 1+(-8)=-7 |
2 | -4 | 2+(-4)=-2 |
-1 | 8 | -1+8=7 |
-2 | 4 | -2+4=2 |
From this list we can see that 1 and -8 add up to -7 and multiply to -8
Now looking at the expression , replace with (notice combines to . So it is equivalent to )
Now let's factor by grouping:
Group like terms
Factor out the GCF of out of the first group. Factor out the GCF of out of the second group
Since we have a common term of , we can combine like terms
So factors to
So this also means that factors to (since is equivalent to )
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Answer:
So factors to
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