SOLUTION: This is an Area Problem. The directions say:Find the dimensions of the rectangle or triangle that has the given area. number 44, the area is 34 square meters. the length of the r

Question 189239This question is from textbook McDougal Littel Algebra 1
: This is an Area Problem.
The directions say:Find the dimensions of the rectangle or triangle that has the given area.
number 44, the area is 34 square meters. the length of the rectangle is (X+11)m and the width is (X-4). I cannot figure out how to start the problem.
THIS IS URGENT SO CAN YOU PLEASE GET BACK TO ME BEFORE TONIGHT. This question is from textbook McDougal Littel Algebra 1

Found 2 solutions by jim_thompson5910, jonvaliente:
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
Because "the area is 34 square meters", this tells us that

Since the "length of the rectangle is (X+11)m", this means that

Also, since "the width is (X-4)", this means that

Start with the area of a rectangle formula

Plug in , and

FOIL

Subtract 34 from both sides.

Combine like terms.

Notice we have a quadratic equation in the form of where , , and

Let's use the quadratic formula to solve for x

Start with the quadratic formula

Plug in , , and

Square to get .

Multiply to get

Rewrite as

Add to to get

Multiply and to get .

Take the square root of to get .

or Break up the expression.

or Combine like terms.

or Simplify.

So the possible answers are or

However, if we plug in into either or , we get

...

Since a negative length or width doesn't make any sense, we must discard this possible solution

So the only solution for "x" is

This means that the length and width are:

Length:

Width:

So the length is 17 meters and the width is 2 meters.
Answer by jonvaliente(64) (Show Source): You can put this solution on YOUR website!
The area of a rectangle is given by the product of its length and width. So from this, we get an equation:
(x+11)*(x-4)=34
Using FOIL we get:

Subtracting 34 from both sides, we get:

Factoring this quadratic equation, we get:

x+13=0 and/or x-6=0
x=-13 and/or x=6
If x=-13, then the length of the rectangle, (x+11)=(-13)+11=-2. But length cannot be negative, so we take x=6
where (x+11)=(6+11)=17=length of the rectangle
(x-4)=6-4=2=width of the rectangle
So you now have a rectangle with dimensions 17m x 2m
Hope this helps.

RELATED QUESTIONS
The directions say: Find the dimensions of the rectangle or triangle that has the given... (answered by jonvaliente,checkley75)
Find the dimensions of the rectangle or triangle that has the given area: Area: 34... (answered by MathLover1)
Find the dimensions of the rectangle or triangle that has the given area. rectangle: (answered by josgarithmetic)
Find the dimensions of the rectangle given that its area is 504m^2.the rectangle has... (answered by Alan3354)
An isosceles triangle has perimeter 64m. Find the dimensions of this triangle that make... (answered by richard1234)
Find the dimensions of the triangle that has the given area (x+3)ft (x+6)ft Area: 119... (answered by Fombitz)
A rectangle has a length that is 2 less than 3 times the width, if the area of this... (answered by TimothyLamb)
How do you find the area for this expression?: Erik has 2000 yards of fencing to enclose... (answered by stanbon)
A rectangle is inscribed fully inside an equilateral triangle. The triangle has a side... (answered by josgarithmetic)