SOLUTION: Hi there,I'm new so im sorry if i do not do something correctly. I am too embarrassed to ask questions in class and... Can you please explain to me how to work out the following pr

Question 189078: Hi there,I'm new so im sorry if i do not do something correctly. I am too embarrassed to ask questions in class and... Can you please explain to me how to work out the following problem?

______

Minus

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I tried this and here is my answer:

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Found 2 solutions by stanbon, jim_thompson5910:
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
please explain to me how to work out the following problem?
[(3+y)/(y^2+9)] - [(y-3)/(9-y^2)]
I tried this and here is my answer:
1 / [(y-3)(y+3)]
------------------------------------
[(3+y)/(y^2+9)] - [(y-3)/(9-y^2)]
lcd = -(y^2+9)(y^2-9)
---------------------------------
Rewrite each fraction with the lcd as its denominator:
= [(y+3)(y^2-9)]/lcd - [(y-3)(y^2+9)]/lcd
Combine the numerators over the lcd:
= [[y^3+3y^2-9y-27] - (y^3-3y^2+9y-27)]]/lcd
= (6y^2-18y)/lcd
= [6y(y-3)]/[-(y^2+9)(y^2-9)]
= -(6y)/[(y^2+9)(y+3)]
============================
Cheers,
Stan H.

Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
You should never feel embarrassed to ask questions. You're asking them now aren't you?

Start with the given expression.

Factor to get (use the difference of squares)

Factor a negative 1 from to get . Also, rearrange the terms.

Cancel out the common terms.

Simplify

Reduce

Multiply both the numerator and denominator of the first fraction by

FOIL

Multiply both the numerator and denominator of the second fraction by

Distribute

Add the fractions.

Combine like terms.

So where

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