SOLUTION: Can someone please help me. I've submitted this problem yesterday at 10:00 am and today at 1:00pm and still haven't gotten a response. Suppose you work in an office and your cu

Algebra.Com
Question 188704: Can someone please help me. I've submitted this problem yesterday at 10:00 am and today at 1:00pm and still haven't gotten a response.
Suppose you work in an office and your current cubicle is a square. The company is moving and your new cubicle will be 2 feet longer on one side and 3 feet shorter on the other.
a) Determine the dimensions of your new cubicle based on your original square, which is x feet per side.


x + 2 would be the side 2 feet longer.


x - 3 would be the side 3 feet shorter.


b) Write the equation for the area of your new cubicle.


(x + 2)(x - 3) Area = Length * Width


Using the FOIL method to multiply the polynomials


Note the "FOILy face".


c) If your old cubicle was 8 feet by 8 feet, is your new cubicle larger or smaller and by how much?


8 * 8 = 64 ft2 Size of original cubicle.


82 - 8 - 6 Substitute in value of x which is 8 in this case.


64 - 14


50 ft2 Size of new cubicle


64 - 50 = 14 ft2 New cubicle is 14 square feet smaller than old cubicle.


Using the example above, develop a similar problem in which you change the size of a shape. Show the same steps as above. No graphics needed.

Answer by jim_thompson5910(35256)   (Show Source): You can put this solution on YOUR website!
a) You are correct. The dimensions are by

b)

Area:


So the area is

--------

c)

Original Area:


New Area:


Difference in Areas:


New cubicle is smaller by 14 square feet (since ). You are correct.


---------------

d)

Let's say that we start with a square again with side lengths of "x". Now one side is lengthened by 5 while the other is shortened by 2.


So the new dimensions would be by


The new area would be

Finally, if , then

Old area:


New area:


Difference in areas:


New area is now 9 square feet larger than the old area.

RELATED QUESTIONS

I submitted this question at 10:00 am and still no response Multiply [(2/3)x +... (answered by nerdybill)
I submitted this problem on yesterday and still have not gotten a respond. Can someone... (answered by ankor@dixie-net.com)
One day the temperature at 8:00 am was 41F and by 1:00Pm the temperature was 61F. What... (answered by Zoop)
I need help setting up this problem so I can solve it. Can anyone please help? A... (answered by checkley75,rmromero)
I submitted this problem yesterday. I recd a response for one of the problems but I'm not (answered by stanbon)
Hello, Help!! Help!! Help!! I have submitted these two problems three time can... (answered by dabanfield)
I have submitted some questions and waiting on a tutor to answer the problems I have not... (answered by chessace)
I wrote this question earlier but I forgot to show what I tried but am not sure if it's... (answered by stanbon,bucky,MathTherapy)
I submitted this problem and I am not quite sure it was done right. Can I get someone to... (answered by vertciel)