SOLUTION: Factor the polynomial completly:
x^3y+2x^2y^2+xy^3
Factor the polinomial completly:
32x^2y-2y^3
Use grouping to factor the polynomial completly:
x^3+x^2-x-1
Use g
Algebra.Com
Question 188463: Factor the polynomial completly:
x^3y+2x^2y^2+xy^3
Factor the polinomial completly:
32x^2y-2y^3
Use grouping to factor the polynomial completly:
x^3+x^2-x-1
Use grouping to factor the polynomial completly"
y^3-5y^2+8y-40
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
I'll do the first two to get you started
# 1
Start with the given expression
Factor out the GCF
Now let's focus on the inner expression
------------------------------------------------------------
Looking at we can see that the first term is and the last term is where the coefficients are 1 and 1 respectively.
Now multiply the first coefficient 1 and the last coefficient 1 to get 1. Now what two numbers multiply to 1 and add to the middle coefficient 2? Let's list all of the factors of 1:
Factors of 1:
1
-1 ...List the negative factors as well. This will allow us to find all possible combinations
These factors pair up and multiply to 1
1*1
(-1)*(-1)
note: remember two negative numbers multiplied together make a positive number
Now which of these pairs add to 2? Lets make a table of all of the pairs of factors we multiplied and see which two numbers add to 2
First Number | Second Number | Sum | 1 | 1 | 1+1=2 |
-1 | -1 | -1+(-1)=-2 |
From this list we can see that 1 and 1 add up to 2 and multiply to 1
Now looking at the expression , replace with (notice adds up to . So it is equivalent to )
Now let's factor by grouping:
Group like terms
Factor out the GCF of out of the first group. Factor out the GCF of out of the second group
Since we have a common term of , we can combine like terms
So factors to
So this also means that factors to (since is equivalent to )
note: is equivalent to since the term occurs twice. So also factors to
------------------------------------------------------------
So our expression goes from and factors further to
------------------
Answer:
So completely factors to
# 2
Start with the given expression
Factor out the GCF
Rewrite as
Factor to get (use the difference of squares)
So completely factors to
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