SOLUTION: Factor the polynomial completly: x^3y+2x^2y^2+xy^3 Factor the polinomial completly: 32x^2y-2y^3 Use grouping to factor the polynomial completly: x^3+x^2-x-1 Use g

Algebra.Com
Question 188463: Factor the polynomial completly:
x^3y+2x^2y^2+xy^3
Factor the polinomial completly:
32x^2y-2y^3
Use grouping to factor the polynomial completly:
x^3+x^2-x-1
Use grouping to factor the polynomial completly"
y^3-5y^2+8y-40

Answer by jim_thompson5910(35256)   (Show Source): You can put this solution on YOUR website!
I'll do the first two to get you started

# 1




Start with the given expression


Factor out the GCF


Now let's focus on the inner expression




------------------------------------------------------------



Looking at we can see that the first term is and the last term is where the coefficients are 1 and 1 respectively.

Now multiply the first coefficient 1 and the last coefficient 1 to get 1. Now what two numbers multiply to 1 and add to the middle coefficient 2? Let's list all of the factors of 1:



Factors of 1:
1

-1 ...List the negative factors as well. This will allow us to find all possible combinations

These factors pair up and multiply to 1
1*1
(-1)*(-1)

note: remember two negative numbers multiplied together make a positive number


Now which of these pairs add to 2? Lets make a table of all of the pairs of factors we multiplied and see which two numbers add to 2

First NumberSecond NumberSum
111+1=2
-1-1-1+(-1)=-2



From this list we can see that 1 and 1 add up to 2 and multiply to 1


Now looking at the expression , replace with (notice adds up to . So it is equivalent to )




Now let's factor by grouping:


Group like terms


Factor out the GCF of out of the first group. Factor out the GCF of out of the second group


Since we have a common term of , we can combine like terms

So factors to


So this also means that factors to (since is equivalent to )


note: is equivalent to since the term occurs twice. So also factors to



------------------------------------------------------------




So our expression goes from and factors further to


------------------
Answer:

So completely factors to






# 2


Start with the given expression


Factor out the GCF


Rewrite as


Factor to get (use the difference of squares)



So completely factors to

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