SOLUTION: Factor Completely z^3(y^2-4)+8(y^2-4) (z^3+8)(y^2-4) (z^3+8)(y-2)(y+2) is the answer i came up with

Question 188458: Factor Completely
z^3(y^2-4)+8(y^2-4)
(z^3+8)(y^2-4)
(z^3+8)(y-2)(y+2) is the answer i came up with
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
Factor Completely
z^3(y^2-4)+8(y^2-4)
(z^3+8)(y^2-4)
(z^3+8)(y-2)(y+2) is the answer i came up with
-----------------
You can factor z^3 + 8
= (z+2)*(z^2 - 2z + 4)

RELATED QUESTIONS
1/x + 2/y - 4/z = 1 2/x + 3/y + 8/z = 0 -1/x + 9/y + 10/z = 5 then solve x, y and... (answered by Fombitz)

y/4+z/4=z/3+x/3=x/2+y/2... (answered by ikleyn)

y/z,if y=4/5 and z=2/3 (answered by Fombitz)