SOLUTION: I understand somewhat how to find teh LCD in problems, but the issue I am running into is when the problem is 5/(x-2)+ 6. The answer I got when I worked the problem was not the sam

Question 187929This question is from textbook
: I understand somewhat how to find teh LCD in problems, but the issue I am running into is when the problem is 5/(x-2)+ 6. The answer I got when I worked the problem was not the same as the book. I got 6x+3\x-2, but the back of the book has 6x-7/x-2
any help would be greatly appreciated! This question is from textbook

Found 3 solutions by Alan3354, solver91311, Earlsdon:
Answer by Alan3354(69443)   (Show Source): You can put this solution on YOUR website!
I understand somewhat how to find teh LCD in problems, but the issue I am running into is when the problem is 5/(x-2)+ 6. The answer I got when I worked the problem was not the same as the book. I got 6x+3\x-2, but the back of the book has 6x-7/x-2
any help would be greatly appreciated!
-------------------------
5/(x-2) + 6 = 5/(x-2) + 6*(x-2)/x-2) Ok so far?
= 5/(x-2) + (6x-12)/(x-2)
= (5 + 6x-12)/(x-2)
= (6x-7)/(x-2)
-----------
How did you get 6x+3 ?

Answer by solver91311(24713)   (Show Source): You can put this solution on YOUR website!

This is the point where you may have gone wrong. I think you might have written:

Which is incorrect because the 6 has to distribute across the (x - 2)

Therefore:

John

Answer by Earlsdon(6294)   (Show Source): You can put this solution on YOUR website!
Starting with:
Multiply the second term (6) by to get both terms over the common denominator of (x-2).
Now add the two fractions.
Simplify the numerator.

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