SOLUTION: Compute the value of the discriminant and give the number of real solution to the quadractic equation
4x^2-x+5=0
Algebra.Com
Question 185733: Compute the value of the discriminant and give the number of real solution to the quadractic equation
4x^2-x+5=0
Answer by checkley77(12844) (Show Source): You can put this solution on YOUR website!
4x^2-x+5=0
x=(1+-sqrt[-1^2-4*4*5])/2*4
x=(1+-sqrt1-80)/8
x=(1+-sqrt-79)/8
x=(1-+8.888i)/8
x=(1+8.888i)/8
x=.125+-1.111i ans.
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