SOLUTION: please help me with these two problems
{{{x^3+64=0}}}
this is how far i got
x^3+64=x+21.3
=(x+21.3)((x^2)-x+21.3)
=(x+21.3)(x^2-x+21.3)
and i have one more problem
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Question 185416This question is from textbook prentice hall mathematics algebra 2
: please help me with these two problems
this is how far i got
x^3+64=x+21.3
=(x+21.3)((x^2)-x+21.3)
=(x+21.3)(x^2-x+21.3)
and i have one more problem
This question is from textbook prentice hall mathematics algebra 2
Answer by Earlsdon(6294) (Show Source): You can put this solution on YOUR website!
1) Solve:
This is the sum of two cubes: and this is factorable as:
and in your problem, A = x and B = 4,so...
, so...
Applying the zero product rule, we get:
or
If then and...
If Use the quadratic formula () to solve:
Simplifying this, we get:
or or these can be written in terms of
} or
So the three roots (there are three because it's a cubic equation) are:
-------------------------------------------------------------------
2) Solve:
This is the difference of two cubes () and this is factorable as: and in this problem, A = x and B = 5, so...
so...
Again, applying the zero product rule, we get:
or so...
If then or
If Use the quadratic formula to solve:
Simplifying, we get:
or which can be written as:
or
So the three roots are:
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