# SOLUTION: 5x3y-125xy 2m3+16 2x3+6x2-3x-9

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 Click here to see ALL problems on Polynomials-and-rational-expressions Question 184928: 5x3y-125xy 2m3+16 2x3+6x2-3x-9 Answer by swiemers(10)   (Show Source): You can put this solution on YOUR website!I'm assuming you are supposed to factor or simply the expressions, so that's how I'll solve them. 1. 5x^3y - 125xy Factor out 5xy and get: 5xy(x^2 - 25) Then you can factor the parentheses as the difference of two squares into: 5xy(x - 5)(x + 5) 2. 2m^3 + 16 Factor out a 2 and get: 2(x^3 + 8) Then use the sum of two cubes rule to factor the parentheses into: 2(x + 2) (x^2 - 2x + 4) 3. 2x^3 + 6x^2 - 3x - 9 This one we need to factor by grouping. First, group the first two terms together: 2x^3 + 6x^2 We can factor out 2x^2 and get: 2x^2(x + 3) Second, group the second two terms together: -3x - 9 We can factor out a -3 and get: -3(x + 3) So all of our factored problem so far is: 2x^2(x + 3) -3(x + 3) When you are factoring by grouping, you rewrite this as two parentheses. The first is what's inside the parentheses - as long as it is THE SAME. The second parentheses is what is left over. So, it would become: (x + 3) (2x^2 - 3) Hope this helps! Good luck! Sandy :-)