SOLUTION: A photo is 4 inches longer than it is wide. A 3-inch border is placed around the photo making the total area of the photo and border 165 square inches. What are the dimensions of t

Algebra ->  Algebra  -> Polynomials-and-rational-expressions -> SOLUTION: A photo is 4 inches longer than it is wide. A 3-inch border is placed around the photo making the total area of the photo and border 165 square inches. What are the dimensions of t      Log On

Ad: Algebra Solved!™: algebra software solves algebra homework problems with step-by-step help!
Ad: Algebrator™ solves your algebra problems and provides step-by-step explanations!

   

Question 184879: A photo is 4 inches longer than it is wide. A 3-inch border is placed around the photo making the total area of the photo and border 165 square inches. What are the dimensions of the photo?

Answer by checkley77(12569) About Me  (Show Source):
You can put this solution on YOUR website!
L=W+4
(L+2*3)(W+2*3)=165
(W+4+6)(W+6)=165
(W+10)(W+6)=165
W^2+16W+60-165=0
W^2+16W-105=0
(W+21)(W-5)=0=0
W-5=0
W=5 ANS. FOR THE WIDTH OF THE PHOTO.
L=5+4=9 ANS. THE LENGTH OF THE PHOTO.
PROOF:
(9+6)(5+6)=165
15*11=165
165=165