# SOLUTION: If four out of five doctors prefer fast food, then at a convention of 445 doctors, how many prefer fast food? I came up with 75.

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 Click here to see ALL problems on Polynomials-and-rational-expressions Question 184429: If four out of five doctors prefer fast food, then at a convention of 445 doctors, how many prefer fast food? I came up with 75. Answer by stanbon(57377)   (Show Source): You can put this solution on YOUR website! If four out of five doctors prefer fast food, then at a convention of 445 doctors, how many prefer fast food? I came up with 75. ---------------- 4:5 is the same as 4x:5x where 4x is the number that prefer fast food. --------------- 4x + 5x = 445 9x = 445 x = 49.44444 ------------------ Then 4x = 197.78 Rounding donw: 197 or the 445 preferred fast food. Cheers, Stan H.