SOLUTION: The length of a rectangle is 4 cm more than the width. If the length is increased by 8 cm and the width is decreased by 4 cm, the area will remain unchanged. Find the original di
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Question 183805: The length of a rectangle is 4 cm more than the width. If the length is increased by 8 cm and the width is decreased by 4 cm, the area will remain unchanged. Find the original dimensions of the rectangle.
Here is what I tried.
L = W + 4
W = W
A = LW
(w + 4)(w)= w^2 + 4w
I got stuck here, which probably means I didn't set it up right to begin with. Thanks for the help!
Answer by halbren(10) (Show Source): You can put this solution on YOUR website!
Your start is correct, you need to do the second part of the problem.
The area of two rectangles is equal
Rectangle 2
L is increased by 8
Width is decreased by 4
Using FOIL method
Since the Area didn't change from the first Rectangle
Move all variables to one side and constants to the other
Since L=W+4
Check your answer
(16+8)(12-4)=(24)(8)=192
The solution works
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