SOLUTION: Solve the equation. t2+1=13/6t
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Question 182125: Solve the equation. t2+1=13/6t
Answer by checkley77(12844) (Show Source): You can put this solution on YOUR website!
t2+1=13/6t
t^2-13t/6+1=0
Using the quadratic equation t = (-b +- sqrt( b^2-4*a*c ))/(2*a) we get:
t=(+13/6+-sqrt[-13/6^2-4*1*1])/2*1
t=(13/6+-sqrt[4.69444-4])/2
t=(13/6+-sqrt.69444)/2
t=(2.16667+-.83333)/2
t=(2.16667+.83333)/2
t=3/2=1.5 ans.
t=(2.166667-.83333)/2
t=1.3333/2
t=.66667 ans.
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