SOLUTION: factor:
p^2-1-4q^2-4q
I tried grouping, including difference of squares, but couldn't factor completely.
Algebra.Com
Question 181856This question is from textbook
: factor:
p^2-1-4q^2-4q
I tried grouping, including difference of squares, but couldn't factor completely.
This question is from textbook
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
If you applied the difference of two squares and grouping you should have obtained:
(p - 1)\right) - 4q(q - 1))
That's as completely factored as anyone can make this one.
John
RELATED QUESTIONS
Please show me steps to factor the equation:
p^2-1-4q^2-4q
Thank... (answered by stanbon)
completely factor the expression 4q^2+27r^4
a. 31q^2+27r^4
b. 27r^4(4q^2+1)
c.... (answered by jim_thompson5910)
determine p so that 4q+3 is a factor of... (answered by jsmallt9)
factor each polynomial completely... (answered by ewatrrr)
Factor as the difference of two squares. Be sure to factor completely.
49x^2 -... (answered by ewatrrr)
Factor as the difference of two squares. Be sure to factor completely.
9x^2 - 1
(answered by ewatrrr)
Having trouble figuring out how to factor this problem.
Factor completely given that... (answered by MathLover1,greenestamps,MathTherapy,math_tutor2020,ikleyn,josgarithmetic)
1+cos ^2Q = 2(cos ^4Q+sin... (answered by Alan3354)
4q^2+4q/12q^2+16q
simplify by removing factors of 1
The simplified form is... (answered by algebrahouse.com)