SOLUTION: I have no clue what to do, can you please help. Add-2 to both sides of the inequality5<3 then divide both sides of the inequality -20>-30 by-2 explain what happens in both examp

Question 179486This question is from textbook Elementary and Intermediate Algebra Concepts and Applications
: I have no clue what to do, can you please help.
Add-2 to both sides of the inequality5<3 then divide both sides of the inequality -20>-30 by-2 explain what happens in both examples and when the direction of the inequality symbol is reversed. Thanks This question is from textbook Elementary and Intermediate Algebra Concepts and Applications

Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
I have no clue what to do, can you please help.
Add-2 to both sides of the inequality5<3 then divide both sides of the inequality -20>-30 by-2 explain what happens in both examples and when the direction of the inequality symbol is reversed.
-----------
Start: 5 > 3 ; that means 5 is to the right of 3 on the number line.
----------
Add -2 to both sides to get 5-2 > 3-2 or 3 > 1; the order of inequality has not
changes when you add -2 (also is you add +2).
------------
Divide -20 < -30 by -2; you will be 10 < 15
Notice that you affect both numbers and you affect the direction of the
inequality.
That is what happens when you multiply or divide an inequality by a
negative number.
=======================
Cheers,
San H.
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