SOLUTION: {{{2/(y^2-1)}}}+3+{{{1/(y+1)}}}

Question 178060: +3+
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
Assume you mean
+ 3 +
:
(y^2-1) is the difference of squares, factor
+ 3 +
:
common denominator would be (y-1)(y+1)

:
combine like terms

:
numerator will factor:

:
cancel (y+1)'s

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