SOLUTION: i'm suppose to factor completely and can you please show the steps, thank you 61) 12x3 + 16x2 – 400x 62) x3 + 3x2 + 2x + 6 63) x2 – 3x + 2

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Question 177243: i'm suppose to factor completely and can you please show the steps, thank you

61) 12x3 + 16x2 – 400x

62) x3 + 3x2 + 2x + 6

63) x2 – 3x + 2

Answer by jim_thompson5910(35256)   (Show Source): You can put this solution on YOUR website!
# 61



Start with the given expression


Factor out the GCF


Now let's try to factor the inner expression




------------------------------------------------------------



Looking at we can see that the first term is and the last term is where the coefficients are 3 and -100 respectively.

Now multiply the first coefficient 3 and the last coefficient -100 to get -300. Now what two numbers multiply to -300 and add to the middle coefficient 4? Let's list all of the factors of -300:



Factors of -300:
1,2,3,4,5,6,10,12,15,20,25,30,50,60,75,100,150,300

-1,-2,-3,-4,-5,-6,-10,-12,-15,-20,-25,-30,-50,-60,-75,-100,-150,-300 ...List the negative factors as well. This will allow us to find all possible combinations

These factors pair up and multiply to -300
(1)*(-300)
(2)*(-150)
(3)*(-100)
(4)*(-75)
(5)*(-60)
(6)*(-50)
(10)*(-30)
(12)*(-25)
(15)*(-20)
(-1)*(300)
(-2)*(150)
(-3)*(100)
(-4)*(75)
(-5)*(60)
(-6)*(50)
(-10)*(30)
(-12)*(25)
(-15)*(20)

note: remember, the product of a negative and a positive number is a negative number


Now which of these pairs add to 4? Lets make a table of all of the pairs of factors we multiplied and see which two numbers add to 4

First NumberSecond NumberSum
1-3001+(-300)=-299
2-1502+(-150)=-148
3-1003+(-100)=-97
4-754+(-75)=-71
5-605+(-60)=-55
6-506+(-50)=-44
10-3010+(-30)=-20
12-2512+(-25)=-13
15-2015+(-20)=-5
-1300-1+300=299
-2150-2+150=148
-3100-3+100=97
-475-4+75=71
-560-5+60=55
-650-6+50=44
-1030-10+30=20
-1225-12+25=13
-1520-15+20=5

None of these pairs of factors add to 4. So the expression cannot be factored

------------------------------------------------------------





Answer:
So factors to





# 62



Start with the given expression


Group like terms


Factor out the GCF out of the first group. Factor out the GCF out of the second group


Since we have the common term , we can combine like terms


So factors to


In other words,







# 63




Looking at the expression , we can see that the first coefficient is , the second coefficient is , and the last term is .


Now multiply the first coefficient by the last term to get .


Now the question is: what two whole numbers multiply to (the previous product) and add to the second coefficient ?


To find these two numbers, we need to list all of the factors of (the previous product).


Factors of :
1,2
-1,-2


Note: list the negative of each factor. This will allow us to find all possible combinations.


These factors pair up and multiply to .
1*2
(-1)*(-2)

Now let's add up each pair of factors to see if one pair adds to the middle coefficient :


First NumberSecond NumberSum
121+2=3
-1-2-1+(-2)=-3



From the table, we can see that the two numbers and add to (the middle coefficient).


So the two numbers and both multiply to and add to


Now replace the middle term with . Remember, and add to . So this shows us that .


Replace the second term with .


Group the terms into two pairs.


Factor out the GCF from the first group.


Factor out from the second group. The goal of this step is to make the terms in the second parenthesis equal to the terms in the first parenthesis.


Combine like terms. Or factor out the common term

---------------------------------------------


Answer:


So factors to .


In other words,


Note: you can check the answer by FOILing to get or by graphing the original expression and the answer (the two graphs should be identical).

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