m + 5
---------------------
2m+3 ) 2m2+13m - 18
-(2m2+3m)
----------------
10m
-(10m+15)
---------
-33
so the remainder is -33/(2m+3)
:
a
Answer:
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website! 2m^2+13m-18/2m+3
----------------------
Set it up as you would a long-division problem
----
Divide 2m into 2m^2 to get m
Multiply m times 2m+3 to get 2m^2+3m
Subtract that from 2m^2 + 13m - 18 to get 10m-18
Divide the 10m by 2m to get 5
Multiply 5 times 2m+3 to get 10m+15
Subtract that from from 10m-18 to get -33
=============================
The quotient is m+5
The remainder is -33
========================
Cheers,
Stan H.