SOLUTION: Can you please help me solve this problem {{{z^2+16z+39}}}? It is supposed to come out in an answer that is in this form [(z+3)(z+13)] but i don't know how to do that.

Question 173918This question is from textbook algerba
: Can you please help me solve this problem ? It is supposed to come out in an answer that is in this form [(z+3)(z+13)] but i don't know how to do that. This question is from textbook algerba

Answer by checkley77(12844) (Show Source): You can put this solution on YOUR website!
z^2+16z+39
What you need to do is factor the term 39 such that the sum, in this case as each of the second & third terms are both plus, of the factors that add up to 16.
Factors are:
1 & 39 sum=40
3 & 13 sum=16 thus you have the 2 terms you need:
(z+3)(z+13)
RELATED QUESTIONS
z^(4)-z^(2)-2z+2 Please could someone help me with the last part of this question.... (answered by josgarithmetic)

Can you help me to solve this? I know that the answer is 0 (x^2yz)/((x-y)(x-z))... (answered by Alan3354)

6(5z-1)-5(z+2)=13(z+1) Can you please help me solve this in algebric form. Thank you (answered by jim_thompson5910)

Could you please help me out with this problem?? Multiply and simplify z^2-2-12 (answered by stanbon)

Please help me solve this equation: {{ z-4/z-3=z+2/z+1... (answered by edjones)

Please help. I am supposed to solve this: z-2/z+1= 5/7(5/7 is a... (answered by ankor@dixie-net.com)

Ive been stuck on this problem for almost 2 weeks now. I just cannot seem to find an... (answered by Earlsdon)

Could you please help me answer this equation: (z^2+9z+14/z^2+11z+28) /... (answered by ewatrrr)

Please help... I tried to solve this, but no result. I eliminated z in 1&2,and 2&3, but... (answered by htmentor,ikleyn)