SOLUTION: I just want to make sure I
'm on the right track.Factoring
x^2-5x+24
x^2+3x-40
x^2-9/16
Algebra.Com
Question 173380: I just want to make sure I
'm on the right track.Factoring
x^2-5x+24
x^2+3x-40
x^2-9/16
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
# 1
Looking at the expression , we can see that the first coefficient is , the second coefficient is , and the last term is .
Now multiply the first coefficient by the last term to get .
Now the question is: what two whole numbers multiply to (the previous product) and add to the second coefficient ?
To find these two numbers, we need to list all of the factors of (the previous product).
Factors of :
1,2,3,4,6,8,12,24
-1,-2,-3,-4,-6,-8,-12,-24
Note: list the negative of each factor. This will allow us to find all possible combinations.
These factors pair up and multiply to .
1*24
2*12
3*8
4*6
(-1)*(-24)
(-2)*(-12)
(-3)*(-8)
(-4)*(-6)
Now let's add up each pair of factors to see if one pair adds to the middle coefficient :
| First Number | Second Number | Sum | | 1 | 24 | 1+24=25 |
| 2 | 12 | 2+12=14 |
| 3 | 8 | 3+8=11 |
| 4 | 6 | 4+6=10 |
| -1 | -24 | -1+(-24)=-25 |
| -2 | -12 | -2+(-12)=-14 |
| -3 | -8 | -3+(-8)=-11 |
| -4 | -6 | -4+(-6)=-10 |
From the table, we can see that there are no pairs of numbers which add to . So cannot be factored.
# 2
Looking at the expression , we can see that the first coefficient is , the second coefficient is , and the last term is .
Now multiply the first coefficient by the last term to get .
Now the question is: what two whole numbers multiply to (the previous product) and add to the second coefficient ?
To find these two numbers, we need to list all of the factors of (the previous product).
Factors of :
1,2,4,5,8,10,20,40
-1,-2,-4,-5,-8,-10,-20,-40
Note: list the negative of each factor. This will allow us to find all possible combinations.
These factors pair up and multiply to .
1*(-40)
2*(-20)
4*(-10)
5*(-8)
(-1)*(40)
(-2)*(20)
(-4)*(10)
(-5)*(8)
Now let's add up each pair of factors to see if one pair adds to the middle coefficient :
| First Number | Second Number | Sum | | 1 | -40 | 1+(-40)=-39 |
| 2 | -20 | 2+(-20)=-18 |
| 4 | -10 | 4+(-10)=-6 |
| 5 | -8 | 5+(-8)=-3 |
| -1 | 40 | -1+40=39 |
| -2 | 20 | -2+20=18 |
| -4 | 10 | -4+10=6 |
| -5 | 8 | -5+8=3 |
From the table, we can see that the two numbers and add to (the middle coefficient).
So the two numbers and both multiply to and add to
Now replace the middle term with . Remember, and add to . So this shows us that .
Replace the second term with .
Group the terms into two pairs.
Factor out the GCF from the first group.
Factor out from the second group. The goal of this step is to make the terms in the second parenthesis equal to the terms in the first parenthesis.
Combine like terms. Or factor out the common term
---------------------------------------------
Answer:
So factors to .
Note: you can check the answer by FOILing to get or by graphing the original expression and the answer (the two graphs should be identical).
# 3
Start with the given expression.
Rewrite as .
Rewrite as .
Notice how we have a difference of squares where in this case and .
So let's use the difference of squares formula to factor the expression:
Start with the difference of squares formula.
Plug in and .
So this shows us that factors to .
In other words .
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