SOLUTION: please help me solve this equation: x+3 over x-5 + 3 over x = 40 over x squared -5x

Question 173136: please help me solve this equation: x+3 over x-5 + 3 over x = 40 over x squared -5x
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
x+3 over x-5 + 3 over x = 40 over x squared -5x
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(x+3)/(x+5) + 3/x = 40/(x^2 - 5x) I think that's what you meant. Using parentheses can eliminate ambiguities.
Find a common DEN. x*(x+5)*(x-5) will work
(x+3)/(x+5) + 3/x = 40/(x^2 - 5x)
--> x(x+3)(x-5)/DEN + 3*(x^2-25)/DEN = 40*(x+5)/DEN
Multiply thru by DEN
--> x(x+3)(x-5) + 3*(x^2-25) = 40*(x+5)
x*(x^2 - 2x - 15) + 3(x^2 - 25) = 40x + 200
x^3 -2x^2 - 15x + 3x^2 - 75 = 40x + 200
x^3 + x^2 - 55x - 275 = 0
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I don't want to work on this any more until I'm sure it's what you intended.

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