Question 170371: How do I solve the following: 49f/5f-35+4f/35f-245
Answer by checkley77(12844)   (Show Source):
You can put this solution on YOUR website! 49f/5f-35+4f/35f-245
IF you mean:
(49f/5f)-35+(4f/35f)-245 then:
49/5-35+4/35-245
49/5+4/35-280
(343+4)/35-280
347/35-280
9.9143-280=-270.086 ans.
Or do you mean:
49f/(5f-35)+4f/(35f-245)
[49f(35f-245)+4f(5f-35)]/(5f-35)(35f-245)
(1,715f^2-12,005f+20f^2-140f)/(175f^2-1,225f-1,225f+8,575)
(1,735f^2-12,145f)/(175f^2-2,250f+8,575)
1,735f(f-7)/(175f^2-2,250f+8,575)
(Denominator has complex roots).
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