SOLUTION: i would like to know if someone can help me with this problem: x ---- x-2 (x over x minus 2) plus -8 ----- x^2-4 (negative 8 over x to

Question 169736This question is from textbook beggining algebra
: i would like to know if someone can help me with this problem:
x
----
x-2 (x over x minus 2)
plus
-8
-----
x^2-4 (negative 8 over x to the second power minus 4)
this problem is in a fraction form i hope i was able to explain this problem right.
thank you! This question is from textbook beggining algebra

Answer by edjones(8007) (Show Source): You can put this solution on YOUR website!
x/(x-2) + -8/(x^2-4)
=x/(x-2) + -8/((x-2)(x+2)) Factor
=(x(x+2)+(-8))/((x-2)(x+2)) LCD
=(x^2+2x-8)/((x-2)(x+2)
=((x+4)(x-2))/((x-2)(x+2)) Factor
=(x+4)/(x+2)
.
Ed

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