SOLUTION: 2ab+2ay+bx+xy

Algebra.Com
Question 168594: 2ab+2ay+bx+xy
Answer by midwood_trail(310)   (Show Source): You can put this solution on YOUR website!
Yu did not state directions but I assume you want to factor, right?
2ab + 2ay + bx + xy
When you have 4 terms, it is best to factor by groups.
2ab + 2ay = group 1
bx + xy = group 2
Factor each group individually.
2ab + 2ay = 2a(b + y)
===============================
bx + xy = x(b + y)
We now have this:
2a(b + y)x(b + y)
Notice that we have two quantities that are the same, which is (b + y).
We only need one of them.
Your final answer is the following two factors:
(2a + x)(b + y)


RELATED QUESTIONS

2ax-2ay-bx+by (answered by MathLover1,03008082502,lenny460)
solve: 1.(2a-7)(a+9)=0 2.64x^2-9=0 3.x(x+3)=18 factor:... (answered by checkley77,KnightOwlTutor)
Factor: 1.28b+2ay+bx+xy 2. y^2-7y-18 3. Y^2-13y+40 4.x^2-x-30 5. 8x^2-14x-15 6.... (answered by stanbon)
ax+bx=a^2+2ab+b^2= (answered by jim_thompson5910)
a^3/x+by=a^2+b^2 x^2+y^2+xy=84 x+y+√xy=14... (answered by Alan3354)
Solve for x and y. bx + ay = 2ab bx - ay = 4ab (answered by ankor@dixie-net.com)
I'm taking intermediate algebra 10 years after I last took it. We've been given a sheet... (answered by Alan3354)
ax+bx=a^2+2ab+b^2= 3ax+6=a^2x+2a= 4x-4=b^2+5b-bx=... (answered by user_dude2008)