SOLUTION: Factor: 1.4x^2+12+9 Factor by using trial factors: 1. 4y2+15y+9 Factor by grouping: 1. 12a^2+8a-28 2. 2y^4+20y^3+18y^2 Factor: 1. a(x+4)+11(x+4)

Question 168587: Factor:
1.4x^2+12+9
Factor by using trial factors:
1. 4y2+15y+9
Factor by grouping:
1. 12a^2+8a-28
2. 2y^4+20y^3+18y^2
Factor:
1. a(x+4)+11(x+4)
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
Factor:
1.4x^2 + 12x + 9
Note that the 4 and the 9, see if it is a perfect square
(2x + 3)(2x + 3)
:
Factor by using trial factors:
1. 4y^2 + 15y + 9
We know that the factors of 9 are probably 3*3, the coefficients of x
have to be different from the previous problem
(4x+3)(x+3)
:
Factor by grouping:
1. 12a^2 + 8a - 28
I can't seem to get this one to factor at all

2. 2y^4 + 20y^3 + 18y^2
2y^2(y^2 + 10y + 9)
2y^2(y^2 + 9y + y + 9)
2y^2(y^2 + 9y) + 2y^2(y + 9)
2y^3(y + 9) + 2y^2(y + 9)
(2y^3 + 2y^2)(y + 9)
2y^2(y + 1)(y + 9)
:
Factor:
1. a(x+4)+ 11(x+4)
Factor out (x+4)
(x+4)(a+11)
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