SOLUTION: (3a-5)/(a^2+4a+3)+(2a+2)/(a+3)=(a-3)/(a+1)

Question 168278This question is from textbook Introductory Algebra
: (3a-5)/(a^2+4a+3)+(2a+2)/(a+3)=(a-3)/(a+1)
This question is from textbook Introductory Algebra

Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
+ =
:
Factor where we can:
+ =
:
Multiply equation by (a+3)(x+1)
(a+3)(a+1)* + (a+3)(a+1)* = (a+3)(a+1)*
:
Cancel out the denominators and you have:
(3a-5) + 2(a+1)(a+1) = (a+3)(a-3)
:
FOIL
(3a - 5) + 2(a^2 + 2a + 1) = a^2 - 9
:
3a - 5 + 2a^2 + 4a + 2 = a^2 - 9
:
Combine like terms on the left:
2a^2 - a^2 + 3a + 4a - 5 + 2 + 9 = 0
:
a^2 + 7a + 6 = 0
:
Factor this to:
(a + 6)(a + 1) = 0
:
a = -6
and
a = -1
:
Check solution of x=-6 in original equation
+ =
Do the math, find the common denominator, and you have;
+ =
:
x=-1 can not be a solution, note that in the last denominator we have division by 0
RELATED QUESTIONS
Add: 4a^+3a-5... (answered by jim_thompson5910)

(a^3-2a^2)-(3a^2-4a^3) (answered by waynest)

(1/3 x 4/5)-(2/5 + 3/6) (2a-3a)-(4a+a)-(2a-a) 22.345 x 66.786... (answered by checkley77)

Please help me solve. {{{(3a-5)/(a^2+4a+3)}}}+{{{(2a+2)/(a+3)}}}={{{(a-3)/(a+1)}}}... (answered by Theo)

Solve. (This one is really hard!) 3a-5/a^2+4a+3 + 2a+2/a+3 =... (answered by ankor@dixie-net.com)

(4a^4-8a^3-3a^2+13a-6)/(2a^3-a^2-3a+2) (answered by jsmallt9)

a^2-7a-18/4a^3 divided by a^2-4a-45/2a^3-4a^2 times... (answered by jsmallt9)

4a-3(a-(2a+1)) (answered by Theo)