SOLUTION: If an object is thrown upward with an initial velocity of 80 ft/sec, its height after t sec is given by h = 80t - 16t^2. Find the number of seconds before the object hits the groun
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-> SOLUTION: If an object is thrown upward with an initial velocity of 80 ft/sec, its height after t sec is given by h = 80t - 16t^2. Find the number of seconds before the object hits the groun
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Question 168270This question is from textbook Introductory Algebra
: If an object is thrown upward with an initial velocity of 80 ft/sec, its height after t sec is given by h = 80t - 16t^2. Find the number of seconds before the object hits the ground. This question is from textbook Introductory Algebra
You can put this solution on YOUR website! By the moment that the object hits the ground, h=0.
Thus, substituting,
0=80t-16t2
factor out t
t(80-16t)=0
t=0 or 80-16t=0
16t=80
t=5
SO, it's 0 or 5 seconds.
HOwever, at t=0, the object is not falling but was about to go up with the initial velocity of 80 ft/sec
So, the answer is that t=5.
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