SOLUTION: A partial solution set is given. Find the complete solution set.
x^5+4x^4+4x^3-x^2-4x-4=0;{1,-2,-2}
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Question 167737: A partial solution set is given. Find the complete solution set.
x^5+4x^4+4x^3-x^2-4x-4=0;{1,-2,-2}
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
A partial solution set is given. Find the complete solution set.
x^5+4x^4+4x^3-x^2-4x-4=0;{1,-2,-2}
------------------------------------
Using synthetic division you get:
1)....1....4....4....-1....-4....-4
.......1....5....9.....8.....4...|..0
-2)....1....3....3....2...|..0
-2)....1....1....1...|..0
Quotient: x^2 + x + 1
Solve with quadratic equation:
x = [1 +- sqrt(1-4*1*1)]/2
x = (1+isqrt(3))/2 or x = (1-isqrt(3))/2
=============================================
Cheers,
Stan H.
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