SOLUTION: Hello, here is my problem: (U^6 + V^6 + 2U^3V^3) / (U^3 -V^3 + U^2V �UV^2) The answer is= (U^2-UV+V^2)^2 / (U-V) I have been working on it for about three hours, I just need the

Question 16575: Hello, here is my problem:
(U^6 + V^6 + 2U^3V^3) / (U^3 -V^3 + U^2V �UV^2)
The answer is= (U^2-UV+V^2)^2 / (U-V)
I have been working on it for about three hours, I just need the steps to help me figure it out. Please and Thanks!

Answer by Earlsdon(6294) (Show Source): You can put this solution on YOUR website!
Ok, here we go. I hope you're good at factoring binomials and trinomials.

LET'S DO THE NUMERATOR FIRST: FACTOR IT.
NOW FACTOR THE FACTORS WHICH ARE BOTH THE SUM OF TWO CUBES.

NOW WE'LL DO THE DENOMINATOR. FACTOR BY GROUPING.
FACTOR THE (U + V)
NOW FACTOR THE (U^2 - V^2), IT'S THE DIFFERENCE OF TWO SQUARES.
OK, NOW WE CAN PUT IT ALL BACK TOGETHER.

NOW, CANCEL THE (U + V)'S LEAVING:
= WE'RE DONE!
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