SOLUTION: Two ships leave port, one sailing east and the other south. Some time later they are 17 mi apart, with the eastbound ship 7 mi farther from port than the southbound ship. How far i

Question 165412This question is from textbook
: Two ships leave port, one sailing east and the other south. Some time later they are 17 mi apart, with the eastbound ship 7 mi farther from port than the southbound ship. How far is each from port? This question is from textbook

Answer by checkley77(12844) (Show Source): You can put this solution on YOUR website!
x^2+(x+7)^2=17^2
x^2+x^2+14x+49=289
2x^2+14x+49-289=0
2x^2+14x-240=0
2(x^2+7x-120)=0
2(x-8)(x+15)=0
x-8=0
x=8 miles for the slowest ship.
8+7=15 miles for the faster ship.
Proof:
8^2+15^2=289
64+225=289
289=289

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