SOLUTION: I am looking for the width of a golden rectangle where the length is given as
36inches.
The formula I have been given is {{{L/W = W/(L-W)}}} where length divided by
width is eq
Algebra ->
Algebra
-> Polynomials-and-rational-expressions
-> SOLUTION: I am looking for the width of a golden rectangle where the length is given as
36inches.
The formula I have been given is {{{L/W = W/(L-W)}}} where length divided by
width is eq
Log On
Question 163715: I am looking for the width of a golden rectangle where the length is given as
36inches.
The formula I have been given is where length divided by
width is equal to width divided by length minus width.
Can you help me? Answer by Edwin McCravy(8914) (Show Source):
Plug in 36 for the length L into
Cross-multiply:
Get 0 on the left, by adding -1296
and +36W to both sides:
Swap sides:
That doesn't factor, so we use the
quadratic formula:
with
Write as the sum of two fractions:
Simplify the second term by dividing 18 and 2 by 2
That's OK like that or you may factor out
9:
Using the plus:
, approximately.
Using the minus:
, approximately.
We can discard the negative answer, since a rectangle
cannot have a negative side, and the width is given by:
inches, approximately.
Edwin
