# SOLUTION: I am looking for the width of a golden rectangle where the length is given as 36inches. The formula I have been given is {{{L/W = W/(L-W)}}} where length divided by width is eq

Algebra ->  Algebra  -> Polynomials-and-rational-expressions -> SOLUTION: I am looking for the width of a golden rectangle where the length is given as 36inches. The formula I have been given is {{{L/W = W/(L-W)}}} where length divided by width is eq      Log On

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 Question 163715: I am looking for the width of a golden rectangle where the length is given as 36inches. The formula I have been given is where length divided by width is equal to width divided by length minus width. Can you help me?Answer by Edwin McCravy(8914)   (Show Source): You can put this solution on YOUR website! Plug in 36 for the length L into Cross-multiply: Get 0 on the left, by adding -1296 and +36W to both sides: Swap sides: That doesn't factor, so we use the quadratic formula: with Write as the sum of two fractions: Simplify the second term by dividing 18 and 2 by 2 That's OK like that or you may factor out 9: Using the plus: , approximately. Using the minus: , approximately. We can discard the negative answer, since a rectangle cannot have a negative side, and the width is given by: inches, approximately. Edwin