SOLUTION: can someone please help me with this problem:
A certain radioactive isotope decays at a rate of 0.25% annually. Determine the half - life of this isotope, to the nearest year.
Algebra.Com
Question 163533: can someone please help me with this problem:
A certain radioactive isotope decays at a rate of 0.25% annually. Determine the half - life of this isotope, to the nearest year.
a. 120 years
b. 277 years
c. 200 years
d. 3 years
Answer by Fombitz(32388) (Show Source): You can put this solution on YOUR website!
The isotope follows this power law as a function of time,
where t is measured in years and is the initial amount of the isotope.
Half life is when ,
.
.
.
Looks like b) 277 years is the closest answer.
RELATED QUESTIONS
Please help. These log word problems are the worst.
A certain radioactive isotope... (answered by ankor@dixie-net.com)
Could someone please help me with this problem? Use the formula N = Ie^kt, where N is the (answered by stanbon)
A certain radioactive isotope decays at a rate of 0.1% annually. Determine the half-life... (answered by stanbon)
A certain radioactive isotope decays at a rate of 0.1% annually. Determine the half-life (answered by ewatrrr)
In the formula A(t) = A0ekt, A is the amount of radioactive material
remaining from an... (answered by scott8148)
a certain radio active isotope decays at a rate of .2% annually. Determine the half life... (answered by scott8148)
Use the formula N = Ie^(kt), where N is the number of items in terms of the initial... (answered by Theo)
Use the formula N = Iekt, where N is the number of items in terms of the initial... (answered by stanbon)
Use the formula N = Iekt, where N is the number of items in terms of the initial... (answered by nerdybill)