SOLUTION: 2x^4=16x I have this so far, but don't know how to finish this problem 2x^4-16x = 0 2x(x^3-8) = 0 Please explain how I finish

SOLUTION: 2x^4=16x I have this so far, but don't know how to finish this problem 2x^4-16x = 0 2x(x^3-8) = 0 Please explain how I finish

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Question 162371This question is from textbook College Algebra an early functions approach
: 2x^4=16x
I have this so far, but don't know how to finish this problem
2x^4-16x = 0
2x(x^3-8) = 0
Please explain how I finish This question is from textbook College Algebra an early functions approach

Answer by josmiceli(19441) (Show Source): You can put this solution on YOUR website!

This is just like saying
Either , , or both have to be
in order for this to be true, so either
and

or

The answer is and
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