SOLUTION: CAN SOMEONE HELP ME WITH THIS PROBLEM Solve the eqation for s. log(9s-7)=r-2 10^(r-2)=9s-7 10^(r-2)+7=9s-7+7 10^(r-2)+7=9s (10^(r-2)+7)/9=9s/9 (10^(r-2))/9 + 7/9 =s

Algebra ->  Algebra  -> Polynomials-and-rational-expressions -> SOLUTION: CAN SOMEONE HELP ME WITH THIS PROBLEM Solve the eqation for s. log(9s-7)=r-2 10^(r-2)=9s-7 10^(r-2)+7=9s-7+7 10^(r-2)+7=9s (10^(r-2)+7)/9=9s/9 (10^(r-2))/9 + 7/9 =s       Log On

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Question 162055: CAN SOMEONE HELP ME WITH THIS PROBLEM
Solve the eqation for s.
log(9s-7)=r-2
10^(r-2)=9s-7
10^(r-2)+7=9s-7+7
10^(r-2)+7=9s
(10^(r-2)+7)/9=9s/9
(10^(r-2))/9 + 7/9 =s

Found 2 solutions by tutor_paul, eperette:
Answer by tutor_paul(490) About Me  (Show Source):
You can put this solution on YOUR website!
Solve for s:
log%28%289s-7%29%29=r-2
====================
First, take the anti-log of both sides of the equation. That means making each side of the equation the exponent of 10:
10%5E%28log%28%289s-7%29%29%29=10%5E%28r-2%29
Use a log property to rewrite the left side of the equation:
9s-7=10%5E%28r-2%29
Solve for s:
9s=10%5E%28r-2%29%2B7
highlight%28s=%2810%5E%28r-2%29%2B7%29%2F9%29
=====================
Good Luck,
tutor_paul@yahoo.com

Answer by eperette(173) About Me  (Show Source):