SOLUTION: CAN SOMEONE HELP ME WITH THIS PROBLEM
Solve the eqation for s.
log(9s-7)=r-2
10^(r-2)=9s-7
10^(r-2)+7=9s-7+7
10^(r-2)+7=9s
(10^(r-2)+7)/9=9s/9
(10^(r-2))/9 + 7/9 =s
Algebra.Com
Question 162055: CAN SOMEONE HELP ME WITH THIS PROBLEM
Solve the eqation for s.
log(9s-7)=r-2
10^(r-2)=9s-7
10^(r-2)+7=9s-7+7
10^(r-2)+7=9s
(10^(r-2)+7)/9=9s/9
(10^(r-2))/9 + 7/9 =s
Found 2 solutions by tutor_paul, eperette:
Answer by tutor_paul(519) (Show Source): You can put this solution on YOUR website!
Solve for s:
====================
First, take the anti-log of both sides of the equation. That means making each side of the equation the exponent of 10:
Use a log property to rewrite the left side of the equation:
Solve for s:
=====================
Good Luck,
tutor_paul@yahoo.com
Answer by eperette(173) (Show Source): You can put this solution on YOUR website!
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