# SOLUTION: CAN SOMEONE PLEASE HELP ME WITH THIS PROBLEM: Total profit is defined as total revenue minus total cost. R(x) and C(x) are the revenue and cost from the sale of x televisions. I

Algebra ->  Algebra  -> Polynomials-and-rational-expressions -> SOLUTION: CAN SOMEONE PLEASE HELP ME WITH THIS PROBLEM: Total profit is defined as total revenue minus total cost. R(x) and C(x) are the revenue and cost from the sale of x televisions. I      Log On

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 Click here to see ALL problems on Polynomials-and-rational-expressions Question 161511This question is from textbook finite mathematics : CAN SOMEONE PLEASE HELP ME WITH THIS PROBLEM: Total profit is defined as total revenue minus total cost. R(x) and C(x) are the revenue and cost from the sale of x televisions. If R(x) = 240x - 0.9x^2 and C(x) = 4000 + 0.6x^2, find the profit from the sale of 100 televisions.This question is from textbook finite mathematics Answer by Alan3354(30993)   (Show Source): You can put this solution on YOUR website!Total profit is defined as total revenue minus total cost. R(x) and C(x) are the revenue and cost from the sale of x televisions. If R(x) = 240x - 0.9x^2 and C(x) = 4000 + 0.6x^2, find the profit from the sale of 100 televisions. --------------------------------- Sub 100 for x ---------------- R(x) = 240x - 0.9x^2 R(100) = 240*100 - 0.9*100*100 R(100) = 24000 - 9000 R(100) = \$15,000 ----------------- C(x) = 4000 + 0.6x^2 C(100) = 4000 + 0.6*100*100 C(100) = \$6,400 --------------- Profit = R - C = \$8,600