# SOLUTION: the area of a rectangle is 45 square cm. if the length is 4 cm. greater than the width, what are the dimensions of the rectangle?

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 Click here to see ALL problems on Polynomials-and-rational-expressions Question 160946: the area of a rectangle is 45 square cm. if the length is 4 cm. greater than the width, what are the dimensions of the rectangle?Answer by nerdybill(7003)   (Show Source): You can put this solution on YOUR website!Let w = width of rectangle then because "the length is 4 cm. greater than the width" w+4 = length of rectangle . Area of any rectangle is width times length: w(w+4) = 45 w^2+4w = 45 w^2+4w-45 = 0 factoring the left: (w+9)(w-5) = 0 w = {-9, 5} We can throw out the negative value, since that doesn't make sense. Therefore w (width) = 5 cm . length: w+4 = 5+4 = 9 cm (length)