SOLUTION: A rectangular garden has perimeter 66ft and area 216ft squared. Find the dimensions of the garden.

Question 160301This question is from textbook Algerbra and Trigonometry structure and method
: A rectangular garden has perimeter 66ft and area 216ft squared. Find the dimensions of the garden. This question is from textbook Algerbra and Trigonometry structure and method

Answer by nerdybill(7384) (Show Source): You can put this solution on YOUR website!
A rectangular garden has perimeter 66ft and area 216ft squared. Find the dimensions of the garden.
.
Let L = length
and W = width
.
Since we have two unknowns, we'll need two equations:
For any rectangle:
2(L+W) = perimeter
2(L+W) = 66
L+W = 33 (equation 1)
.
For any rectangle:
LW = area
LW = 216 (equation 2)
.
Solve equation 1 for L:
L+W = 33
L = 33-W
.
Substitute the above into equation 2 and solve for W:
LW = 216
(33-W)W = 216
33W-W^2 = 216
0 = W^2-33W+216
0 = (W-24)(W-9)
W={24,9}
.
Dimensions:
length is 24 feet
width is 9 feet

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