SOLUTION: can someone please help me with this problem: Complete the square and write the equation in standard form. Then give the center and radius of the circle. x^2^+ y^2 - 2x

SOLUTION: can someone please help me with this problem: Complete the square and write the equation in standard form. Then give the center and radius of the circle. x^2^+ y^2 - 2x - 4y

Question 159699: can someone please help me with this problem:
Complete the square and write the equation in standard form. Then give the center and radius of the circle.
x^2^+ y^2 - 2x - 4y - 4 = 0
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!

First, put the constant term on the right:

Divide the coefficient on the first degree x term by 2. .

Square the result and add that result to both sides.

Repeat the process with the coefficient on the first degree y term

,

Rearrange the terms:

Now factor the x terms:

And factor the y terms:

Put the pieces back together:

Now, use the fact that a circle of radius centered at (,) has an equation to determine that your circle is centered at (,) and has a radius of

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