SOLUTION: Division by inspection
Please help me solve the following problem:
27 a(cubed) + b(cubed) divided by 3a+b
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Question 156564: Division by inspection
Please help me solve the following problem:
27 a(cubed) + b(cubed) divided by 3a+b
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
27 a(cubed) + b(cubed) divided by 3a+b
= [(3a)^3 + b^3] / [3a+b]
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You have "a difference of cubes.
That factors as (3a+b)((3a)^2 -(3a)b+b^2)
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The 3a+b factors in the numerator and in the denominator cancel and you get:
= (3a)^2 - (3a)b + b^2
= 9a^2 - 3ab + b^2
========================
Cheers,
Stan H.
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