SOLUTION: I am currently working on factoring trinomials. I need help factoring the equation: {{{2x^2-6x+2}}} This problem comes from the Intermediate Algebra: Graphs and Functions (Third Ed

Question 155562This question is from textbook
: I am currently working on factoring trinomials. I need help factoring the equation: This problem comes from the Intermediate Algebra: Graphs and Functions (Third Edition) by the Houghton-Miffler Company.
Chapter 1, section 4, page 48, problem number 32. Please help me and thank you very much. This question is from textbook

Found 2 solutions by checkley77, stanbon:
Answer by checkley77(12844) (Show Source): You can put this solution on YOUR website!
2x^2-6x+2
Using the quadratic equatio: we get:
x=(6+-sqrt[-6^2-4*2*2])/2*2
x=(6+-sqrt[36-16])/4
x=(6+-sqrt20}/4
x=(6+-4.472)/4
x=(6+4.472)/4
x=10.472/4
x=2.618 Answer.
x=(6-4.472)/4
x=1.528/4
x=.382 Answer.

Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
2x^2-6x+2
Find the roots using the quadratic formula
x = [36 +- sqrt(36 - 4*2*2)]/4
x = [36 +- sqrt(20)]/4
x = [36 +- 2sqrt(5)]/4
x = 9 + (1/2)sqrt(5) or x = 9 - (1/2)sqrt(5)
Factors:
((x-9) - (1/2)sqrt(5)) ((x-9) + (1/2)sqrt(5))
================
Cheers,
Stan H.

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