I can't tell whether the divisor is or
so I'll do it both ways. With divisor
÷
Rearrange the numerator in descending order:
÷
There is a missing constant term on the right end
so we put 0
÷
(-1/3)x³ + 0x² + 2x + 13
--------------------------------
x - 6) (-1/3)x4 + 2x³ + 2x² + x + 0
(-1/3)x4 + 2x³
--------------
0x³ + 2x²
0x³ + 0x²
---------
2x² + x
2x² -12x
--------
13x + 0
13x - 78
--------
78
Answer:
--------------------------------
With divisor
÷
Rearrange the numerator in descending order:
÷
There is a missing constant term on the right end
so we put 0
÷
(1/3)x³ - 4x² + 22x - 133
------------------------------------
-x - 6) (-1/3)x4 + 2x³ + 2x² + x + 0
(-1/3)x4 - 2x³
--------------
4x³ + 2x²
4x³ + 24x²
---------
-22x² + x
-22x² - 132x
------------
133x + 0
133x + 798
-------------
-798
Answer:
Edwin