SOLUTION: [(2^2)(x^5)(y^-3)(z^4)/(4^0)(x^-2)(y^-8)(z^5)^3]

SOLUTION: [(2^2)(x^5)(y^-3)(z^4)/(4^0)(x^-2)(y^-8)(z^5)^3]

Algebra.Com

Question 153637: [(2^2)(x^5)(y^-3)(z^4)/(4^0)(x^-2)(y^-8)(z^5)^3]
Answer by orca(409) (Show Source): You can put this solution on YOUR website!
Use the formulas:

So

=
=
=
=

RELATED QUESTIONS
Solve {{{system(x+2*y-z = 5, 2*x-4*y+z = 0, 3*x+2*y+2*z = 3)}}} (answered by jim_thompson5910)

1/x + 2/y - 4/z = 1 2/x + 3/y + 8/z = 0 -1/x + 9/y + 10/z = 5 then solve x, y and... (answered by Fombitz)

solve for x,y and z 1. x+y-2z=5 2. x+z=4 3.... (answered by Alan3354)

y/4+z/4=z/3+x/3=x/2+y/2... (answered by ikleyn)

if z=x+iy , z* conj(z)^3+conj(z)*z^3=350, then (x,y)=..[(2,1) ,(3,4) ,(4,3)... (answered by ikleyn)

3 over 2 x - 5 over 3y + 1 over 6 z =0 for y when x=4 and z... (answered by ilana,MathLover1)

Solve each system x+2/6 - y+4/3 + z/2 = 0 x+1/2 + y-1/2 - z/4 = 9/2 x-5/4 + y+1/3 +... (answered by lynnlo)

y/z,if y=4/5 and z=2/3 (answered by Fombitz)

If x>0,y>0,z>0 and x+y+z=1,prove that {{{x/2-x + y/2-y +... (answered by darq)