SOLUTION: what is 2y to the third minus 7y squared minus 15y factored?
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Question 150701: what is 2y to the third minus 7y squared minus 15y factored?
Found 2 solutions by Earlsdon, jim_thompson5910:
Answer by Earlsdon(6294) (Show Source): You can put this solution on YOUR website!
Factor:
Notice that every term has a factor of y, so you can factor a y.
Now look at the trinomial in parentheses.
The first term can be factored as and the last term has factors of:
-15 = -1*15 or 1(-15)
-15 = -3*5 or 3(-5)
To get the middle coefficient of -7, do 2*(-5)+1(3) = -10+3 = -7
So you can try:
...and this works.
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
Start with the given expression
Factor out the GCF
Now let's focus on the inner expression
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Looking at we can see that the first term is and the last term is where the coefficients are 2 and -15 respectively.
Now multiply the first coefficient 2 and the last coefficient -15 to get -30. Now what two numbers multiply to -30 and add to the middle coefficient -7? Let's list all of the factors of -30:
Factors of -30:
1,2,3,5,6,10,15,30
-1,-2,-3,-5,-6,-10,-15,-30 ...List the negative factors as well. This will allow us to find all possible combinations
These factors pair up and multiply to -30
(1)*(-30)
(2)*(-15)
(3)*(-10)
(5)*(-6)
(-1)*(30)
(-2)*(15)
(-3)*(10)
(-5)*(6)
note: remember, the product of a negative and a positive number is a negative number
Now which of these pairs add to -7? Lets make a table of all of the pairs of factors we multiplied and see which two numbers add to -7
First Number | Second Number | Sum | 1 | -30 | 1+(-30)=-29 |
2 | -15 | 2+(-15)=-13 |
3 | -10 | 3+(-10)=-7 |
5 | -6 | 5+(-6)=-1 |
-1 | 30 | -1+30=29 |
-2 | 15 | -2+15=13 |
-3 | 10 | -3+10=7 |
-5 | 6 | -5+6=1 |
From this list we can see that 3 and -10 add up to -7 and multiply to -30
Now looking at the expression , replace with (notice adds up to . So it is equivalent to )
Now let's factor by grouping:
Group like terms
Factor out the GCF of out of the first group. Factor out the GCF of out of the second group
Since we have a common term of , we can combine like terms
So factors to
So this also means that factors to (since is equivalent to )
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So our expression goes from and factors further to
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Answer:
So factors to
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