SOLUTION: {{{x^2=4y^2-z^2-4xy}}}
Algebra.Com
Question 147143:
Answer by mangopeeler07(462) (Show Source): You can put this solution on YOUR website!
The original equation would become . Just subtract the right side from the left (which means change the signs). You cannot go further than that I believe.
however, if you want to solve for x, just do this: .
RELATED QUESTIONS
x^2-4xy+4y^2=36 (answered by Fombitz)
yx^2-4xy+4y (answered by Fombitz)
what is x^2 -4xy+4y^2/... (answered by Fombitz)
factor:... (answered by Earlsdon)
Factorise:
x^2 - 2x + 4xy + 4(y^2) - 4y -... (answered by vleith)
factor 15x^2 -4xy... (answered by user_dude2008,stanbon)
factor 15x^2 +4xy... (answered by checkley77)
did i factor this right?
5x^2-4xy+5x-4y
5x^2-4xy+5x-4y
(5x^2*4xy+5x)-4y... (answered by stanbon)
factorise x^2+4y^216z^2+4xy+16yz+8zx and find the value when x=2, y=-1 and... (answered by ikleyn,Shin123)