SOLUTION: how would i do this?
Factor the following polynomial completely.
y2 + 12y + 36=
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Question 146261: how would i do this?
Factor the following polynomial completely.
y2 + 12y + 36=
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
Looking at we can see that the first term is and the last term is where the coefficients are 1 and 36 respectively.
Now multiply the first coefficient 1 and the last coefficient 36 to get 36. Now what two numbers multiply to 36 and add to the middle coefficient 12? Let's list all of the factors of 36:
Factors of 36:
1,2,3,4,6,9,12,18
-1,-2,-3,-4,-6,-9,-12,-18 ...List the negative factors as well. This will allow us to find all possible combinations
These factors pair up and multiply to 36
1*36
2*18
3*12
4*9
6*6
(-1)*(-36)
(-2)*(-18)
(-3)*(-12)
(-4)*(-9)
(-6)*(-6)
note: remember two negative numbers multiplied together make a positive number
Now which of these pairs add to 12? Lets make a table of all of the pairs of factors we multiplied and see which two numbers add to 12
First Number | Second Number | Sum | 1 | 36 | 1+36=37 |
2 | 18 | 2+18=20 |
3 | 12 | 3+12=15 |
4 | 9 | 4+9=13 |
6 | 6 | 6+6=12 |
-1 | -36 | -1+(-36)=-37 |
-2 | -18 | -2+(-18)=-20 |
-3 | -12 | -3+(-12)=-15 |
-4 | -9 | -4+(-9)=-13 |
-6 | -6 | -6+(-6)=-12 |
From this list we can see that 6 and 6 add up to 12 and multiply to 36
Now looking at the expression , replace with (notice adds up to . So it is equivalent to )
Now let's factor by grouping:
Group like terms
Factor out the GCF of out of the first group. Factor out the GCF of out of the second group
Since we have a common term of , we can combine like terms
So factors to
So this also means that factors to (since is equivalent to )
note: is equivalent to since the term occurs twice. So also factors to
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Answer:
So factors to
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