SOLUTION: (x+4)^3

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Question 145763This question is from textbook intermediate algebra
: (x+4)^3This question is from textbook intermediate algebra

Answer by jim_thompson5910(28598) About Me  (Show Source):
You can put this solution on YOUR website!
%28x%2B4%29%5E3 Start with the given expression

%28x%2B4%29%28x%2B4%29%28x%2B4%29 Expand


%28x%5E2%2B8x%2B16%29%28x%2B4%29 Foil the first two binomials


%28x%2B4%29%28x%5E2%2B8x%2B16%29 Rearrange the terms



x%28x%5E2%2B8x%2B16%29%2B4%28x%5E2%2B8x%2B16%29 Expand. Remember, %28a%2Bb%29%28c%2Bd%2Be%29 expands to a%28c%2Bd%2Be%29%2Bb%28c%2Bd%2Be%29


Distribute.


x%5E3%2B8%2Ax%5E2%2B16%2Ax%2B4%2Ax%5E2%2B32%2Ax%2B64 Multiply.


x%5E3%2B12%2Ax%5E2%2B48%2Ax%2B64 Now combine like terms.


So %28x%2B4%29%5E3 expands to x%5E3%2B12%2Ax%5E2%2B48%2Ax%2B64.


In other words, %28x%2B4%29%5E3=x%5E3%2B12%2Ax%5E2%2B48%2Ax%2B64.