SOLUTION: Evaluate k^2-5 when k =-6

Algebra.Com
Question 145142: Evaluate k^2-5 when k =-6
Answer by BrittanyM(80)   (Show Source): You can put this solution on YOUR website!
For this problem, we've been given an expression and a value, so all we have to do is substitute the given value for the variable and solve.

We have:

-5

And we are given k=-6

-5

Since squared only means (-6) x (-6), we have a positive 36.

36-5 = 31

RELATED QUESTIONS

Sum of (1, 5 k(k+1)/2, 25 k(k+1)(k+2)/6, 125k(k+1)(k+2) (k+3)/24, ……... (answered by robertb)
k^-1(x) when k(x) =... (answered by stanbon)
How would simplify this complex fraction:... (answered by richwmiller)
How do you solve for k in this equation:... (answered by Fombitz)
1) Evaluate. s21 for 23+20+17+14+... enter only the sum. 2) Evaluate. 13 Σ... (answered by ikleyn)
4(k-6)-(3k+2)=-5 (answered by Boreal)
Given that k=2.5, evaluate p = 1- 1/k^2... (answered by Fombitz)
k/15+5=k/6-10 solve for... (answered by checkley77)
Find the Value of K K.......3+K.........-10 1-K......2-K......... 5 = 48 2... (answered by Edwin McCravy)