SOLUTION: I'm having trouble factoring these algebraic expressions, the rest of my problems weren't bad, but I cannot figure these three out, any help would be appreciated. thanks. 6x^2

Question 144119: I'm having trouble factoring these algebraic expressions, the rest of my problems weren't bad, but I cannot figure these three out, any help would be appreciated. thanks.
6x^2 - 28x + 16
x^4 + 2x^3 - 3x - 6
x^8 - 1
Thanks.
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
6x^2 - 28x + 16
= 2(3x^2 - 14x + 8)
= 2(3x^2-12x-2x+8)
= 2(3x(x-4)-2(x-4))
= 2(x-4)(3x-2)
=========================
x^4 + 2x^3 - 3x - 6
= x^3(x+2) -3(x+2)
= (x+2)(x^3-3)
= [(x+2)][(x-3^(1/3))][x^2-3(x^(1/3))+3^(2/3)]
-----------------------------
x^8 - 1 (x^4+1)(x^4+1)
= (x^4+1)(x^2+1)(x+1)(x-1)
============================
Cheers,
Stan H.

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